)Prove that 9+3/7 is irrational.
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Answer:
Step-by-step explanation:
Let us assume 9+3√7 is rational
Therefore 9+3√7=a/b
3√7=a/b-9
3√7=a-9b/b
√7=a-9b/3b
Therefore a-9b/3b is in the form of a/b which is rational number.
But this is contradicts the fact is that √7 is irrational number.
Therefore our assumption is wrong and 9+3√7 is an irrational number.
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