prove that 9-√7 is irrational
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Assume 9-√7 is rational
Now bring 9 to the other side
-> -√7 =-9
-> √7 =9
But we know that 9 is a rational no and √7 is an irrational no
A rational is never equal to an irrational number
Therefore 9-√7 is irrational
Now bring 9 to the other side
-> -√7 =-9
-> √7 =9
But we know that 9 is a rational no and √7 is an irrational no
A rational is never equal to an irrational number
Therefore 9-√7 is irrational
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