Math, asked by shagun163, 11 months ago

. Prove that: 9 sec²A-5 tan²A = 5+ 4 sec²A

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Answered by aditi346454

3

Answer:

here is the solution of ur ques

i hope it will help u☺☺

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Answered by jigyasasewada

0

LHS:- 9sec²A-5tan²A

9sec²A-5(sec²A-1) [tan²A=sec²A-1]

9sec²A-5sec²A+5

4sec²A+5=RHS

LHS=RHS

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