Prove that: 9secA - 9tan2A = 9
Answers
Answered by
7
Answer:
To prove:- 9sec^2A-9tan^2A=9
=> 9(sec^2A-tan^2A)
=> Using identity sec^2A-tan^2A= 1
=> 9×1
=> 9
Hope it helps..✌️
Step-by-step explanation:
Similar questions