Prove that a {0,0}b,{7,0}.c{7,5}and d{0,5}are the vertices of a rectangle?
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Step-by-step explanation:
let the vertices of a parallelogram be A(4,5),B(7,6),C(6,3)D(3,2)
So by distance formula we have,
Distance between two points =
(x
2
−x
1
)
2
+(y
2
−y
1
)
2
AB=
(7−4)
2
+(6−5)
2
=
9+1
=
10
BC=
(6−7)
2
+(3−6)
2
=
1+9
=
10
CD=
(3−6)
2
+(2−3)
2
=
9+1
=
10
AD=
(3−4)
2
+(2−5)
2
=
1+9
=
10
∴ AB=CD and BC=AD
∴ Opposite sides are equal
Hence,ABCD is a parallelogram (Proved)
Also,AB=BC=CD=AD=
10
i.e. all the sides are
equal
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