Prove that a^(0) = 1.
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Answer:
a^0 = a^(1 - 1)
a^0 = [a^1] x [a^(-1)]
a^0 = a x (1/a) [since a^1 = a and a^(-1) = 1/a]
a^0 = a / a
a^0 = 1
Answered by
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Take a any number ,
a^1= a
a^2 =a x a
a^3 = a x a x a
Now you can notice a pattern that when a^3 is divided by a , you get a^(3-1) i.e a^2
Similarly ..., a1 = a^2 divided by a
And thus a^0 will be equal to a ^1 divided by a
Now we know a^1 = a
And thus a/a = 1
So a^0= 1
Hence proved , please thank this answer and mark this answer as brainiest answer if you understood
a^1= a
a^2 =a x a
a^3 = a x a x a
Now you can notice a pattern that when a^3 is divided by a , you get a^(3-1) i.e a^2
Similarly ..., a1 = a^2 divided by a
And thus a^0 will be equal to a ^1 divided by a
Now we know a^1 = a
And thus a/a = 1
So a^0= 1
Hence proved , please thank this answer and mark this answer as brainiest answer if you understood
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