prove that A(1, 1) B(2, 2) and C(3, 3) lie in same line
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we will find
d(AB)=√(2-1)^2+(2-1)^2
=√(1)^2+(1)^2
=√1+1
=√2
d(BC)=√(3-2)^2+(3-2)^2
=√1+1
=√2
d(AC)=√(3-1)^2+(3-1)^2
=√(2)^2+(2)^2
=√4+4
=√8
=√4*2
=2√2
d(AC)=d(AB)+d(BC)
The points A(1, 1) B(2, 2) and C(3, 3) lie in same line
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