Math, asked by sagarbarnwal721, 8 months ago

Prove that
(a-1÷a-1+b-1)+(a-1÷a-1-b-1)=2b2÷b2-a2

Answers

Answered by Tanusdalvi2111

11

Answer:

(a-1÷a-1+b-1)+(a-1÷a-1-b-1)=2b2÷b2-a2

= 2b2 / b2 - a2

Step-by-step explanation:

= a-1÷a-1+b-1)+(a-1÷a-1-b-1)=2b2÷b2-a2

= a-1(a-1/ (a-1 + b-1) + a-1/ (a -1 - b-1)

= a-1 (a-1-b-1)+a-1 (a-1+b-1) /a-2- b-2

= a-2+a-2/a-2- b-2

= 2 a-2/a-2- b-2

= 2/a2/1/a2- 1/b2

= 2/a2 / b2 - a2 / a2 b2

= 2b2 / b2 - a2

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