Question

prove that a^-1/a^-1+b^-1+a^-1/b^-1=2b^2/b^2-a^2​

Answer 1

Answer:

(a+b)^(1/2) = a^(1/2) + (1/2)/1! a^(-1/2)b^1 + (1/2)(-1/2)/2! a^(-3/2)b^2 + (1/2)(-1/2)(-3/2)/3! a^(-5/2)b^3 ... The exponents on a and b always add up to 1/2, and the numeric coefficient "1/2 choose n" (similar in construction to m-choose-n for m integer, although without the usual combinatorial applications) has a falling factorial in the numerator starting with factor 1/2 and

Ad related to: prove that a^-1/a^-1 b^-1 a^-1/b^-1=2b^2/b^2-a^2​

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