Prove that:
(a-¹/a-¹ + b-¹) + (a-¹ - b-¹)= 2b²/b² - a²
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negative exponents invert the fraction and the exponent will be positive:
(1 / a + 1 / b) ² -> the square is still negative, then inverted once more fractions.
however, should now reverse all fraction, since it is all high within 2
1-----------(1 / a + 1 / b) ²
taking notable products are:
1----------(1 / a² + 2 / + 1 ab / b²)
taking MMC in the denominator:
1----------------- -> Multiply the 1st fraction byb² + ab + 2nd of reverse a²----------------a²b²
a²b²-----------b² + 2ab + a² -> or: a²b² / (b + a) ²
(1 / a + 1 / b) ² -> the square is still negative, then inverted once more fractions.
however, should now reverse all fraction, since it is all high within 2
1-----------(1 / a + 1 / b) ²
taking notable products are:
1----------(1 / a² + 2 / + 1 ab / b²)
taking MMC in the denominator:
1----------------- -> Multiply the 1st fraction byb² + ab + 2nd of reverse a²----------------a²b²
a²b²-----------b² + 2ab + a² -> or: a²b² / (b + a) ²
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