Prove that A(2,-3), B(1, 4), C(4, 13) and D(5, 6) form the vertices of a parallelogram.
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Answered by
4
Answer:
Step-by-step explanation:
Slope of ║ lines is the same:
In quadrilateral ABCD:
Slope of AB is
(4 - (-3)) / (1 - 2) = - 7
Slope BC is
(13 - 4) / (4 - 1) = 9/3 = 3
Slope of CD is
(6 - 13) / (5 - 4) = - 7
Slope of AD is
(6 - (-3)) / (5 - 2) = 3
Thus, in quadrilateral ABCD
AB ║ CD and BC ║ AD ===> ABCD is parallelogram
Answered by
2
Answer:
Step-by-step explanation:
Slope of ║ lines is the same:
In quadrilateral ABCD:
Slope of AB is
(4 - (-3)) / (1 - 2) = - 7
Slope BC is
(13 - 4) / (4 - 1) = 9/3 = 3
Slope of CD is
(6 - 13) / (5 - 4) = - 7
Slope of AD is
(6 - (-3)) / (5 - 2) = 3
Thus, in quadrilateral ABCD
AB ║ CD and BC ║ AD ===> ABCD is parallelogram
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