Question

Prove that a^2+b^2+c^2-ab-bc-ca is always non-negative for all values of a,b and c.​

Answer 1

Answer:

∴ [(a − b)2 + (b − c)2 + (c − a)2] ≥ 0 and {(a − b)2 + (b − c)2 + (c − a)2}/2= 0 when a = b = c. Hence, a2 + b2 + c2 – ab – ac - bc is always non-negative for all its values of a, b and c

Step-by-step explanation:

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