Question

prove that a(3, -3) b(5, -1) c(3, -1) are the vertices of an isosceles right triangle. find the area of the triangle​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

We have, A(3,-3) B(5'-1) and C(3,-1)

Applying distance formula we get,

AB= √{(5-3)^2+(-1+3)^2}

= √(2^2+2^2)

= √(4+4)

= √8

= 2√2

BC= √{(3-5)^2+(-1+1)^2}

= √(-2^2+0)

=√4

=2

CA= √{(3-3)^2+(-3+1)}

= √{0+(-2^2)}

=√4

=2

So,BC=CA

Hence, triangle ABC is an isosceles triangle.