Question

prove that a) 3+√5 are irrational no​

Answer 1

Answer:

Hello dude

Here is your answer..

Step-by-step explanation:

Let us assume that 3 + √5 is a rational number.

Now,

3 + √5 = (a ÷ b)

[Here a and b are co-prime numbers]

√5 = [(a ÷ b) - 3]

√5 = [(a - 3b) ÷ b]

Here, {(a - 3b) ÷ b} is a rational number.

But we know that √5 is a irrational number.

So, {(a - 3b) ÷ b} is also a irrational number.

So, our assumption is wrong.

3 + √5 is a irrational number.

Hence, proved.

Hope Helpful ✌️

Answer 2

Step-by-step explanation:

→ a and b both are co-prime numbers and 5 divide both of them. So, √5 is a irrational number.

thank you

if tt helpful please thank