Math, asked by soumya247, 8 months ago

PROVE THAT a^3+b^3+c^3-3abc=0​

Answers

Answered by sachi2007singh
2

Answer:

Step-by-step explanation:

a^3 + b^3 + c^3 = (a+b + c)(a^2 +b^2+c^2-ab-bc-ca) + 3abc

If a+b+c=0

a3+b3+c3-3abc

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