prove that a 3x square +3y square -6x+4y-1=0
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Step-by-step explanation:
-6x+4y-1=0
x=2/3y-1/6
put the value of x in equation
-12/3y+1+4y-1=0
-12/3y+4y=0
these are real numbersare no solution
-12y+12y^2=0
y=0 or y=1
put value of y
-6x+3=0
-6x=-3
x=1/2
vluebofv 3x^2+3y^2
3/4+3
3+12/4
15/4
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