Prove that ( a + b) ( 1/a + 1/b) >4
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options: 1/a<1/b or 1/a>1/b
If 1/a<1/b then a*1/a<b*1/b yields 1<1 is false.
2.
a-b<0
1a−1b=b−aab=−(a−b)abR0
R is the relationship, here > or <.
a-b<0 thus -(a-b)>0. ab>0 yields 1a−1b>0 and so
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