Question

prove that |(A×B)2|+(A.B)2 = A2B2​

Answer 1

Answer:

1×1+2+1.1+2=A3B3

Explanation:

like this is it prove

Answer 2

TO PROOF

: {|A×B|² + |A.B|² =A²B²}

Taking Left Hand Side

|A×B|² + |A.B|²

Since;

A×B=|A||B| sin a

and

A.B=|A||B| cos a

then

=>|A×B|² + |A.B|²

=> (AB sin a)² +(AB cos a)²

=> A²B² (sin a + cos a)²

=> A²B² (1)

=> A²B²