prove that (a+b)2=a2+2ab+b2
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Answer:
(a+b)2=(a+b)(a+b)
=(a+b)(a)+(a+b)(b)
=a2+ab+ab+b2
=a2+2ab+b2
hence proved
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Hello !
Here , we have to prove that (a+b)²= a²+2ab+b².
So let's start,
(a+b)²
→ (a+b)×(a+b)
→ (a+b)(a+b)
→ [a×(a+b)]+[b×(a+b)]
→ [(a×a)+(a×b)]+[(b×a)+(b×b)]
→ [(a²)+(ab)]+[(ba)+(b²)]
→ (a²)+(ab)+(ba)+(b²)
Since, a×b = b×a (communicative property) ba = ab.
→ (a²)+(ab)+(ab)+(b²)
→ a² + 2 × ab + b²
→ a²+2ab+b²
Hence proved✓
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