Question

prove that (a-b)², a²+b², (a+b)² are in AP.

Answer 1

Step-by-step explanation:

(a-b)^2, a^2+b^2, (a+b)^2

a^2, (a+b)^2,a^2+b^2

Therefore (a-b)^2,a^2+b^2,(a+b)^2=a^2-b^2,(a+b)^2,a^2+b^2