prove that |a•b|² = a²b²-(a•b)²
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a x b= a b sin∅ .n, where a=lal and b=lbl (а х b)² = a² b² sin² (n)² = a² b² sin²∅ a²b²( 1-cos²∅)=a² b² - a² b² cos²∅ lal² lbl² -(a.b)² (∵ (n)²= 1).
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