Question

Prove+that+(a-b)2plus+(b-c)2=0then+a=b=c

Answer 1

Answer:

True

Step-by-step explanation:

When a, b, c ∈ R

$(a-b)^2+(b-c)^2=0$

For real number R, $R^2\geq 0$. --- 1

$(a-b)^2\geq 0$ From 1 --- 2

$(b-c)^2\geq 0$ From 1 --- 3

Hence, $(a-b)^2=0$, $(b-c)^2=0$.

And hence $a-b=0$, $b-c=0$.

And hence $a=b=c$.

Hence, proved.

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