Question

PROVE THAT- (a+b)^3=a^3+3a^2b+3ab^2+b^3 (x+a)(x-b)=x^2-(a+b)x+ab BEST ANSWER WILL BE MARKED AS BRAINLIEST

Answer 1

Answer:

[\frac{ax-b+x-ab}{a{x}^{2}-abx}, \quad \left(x\ne 0;x\ne b\right)\] ... Take out common factor \(\left(x-b\right)\) in the numerator. \[=\frac{\left(x ... \begin{align*} \frac{6a^2 - 7a - 3}{3ab + b} &= \frac{(2a-3)(3a+1)}{b(3a + 1)} \\ &= \frac{2a-3}{b} \end{align*} ... \(\dfrac{b^2+10b+21}{3(b^2-9)} \div \dfrac{2b^2+14b}{30b^2-90b}\).

Step-by-step explanation:

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Answer 2

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