Question

prove that (A+B)3=A3+B3+3A2B+3AB2​

Answer 1

Answer:

(a+b)^3=(a+b)^2(a+b)

=(a^2+2ab+b^2)(a+b)

=a^3+2a^2b+ab^2+a^2b+2ab^2+b^3

=a^3+3a^2

b+3ab^2+b^3

hence proved