Prove that:
(a - b)3 + (b - c)3 +(c - a)3 = 3(a - b)(b - c)(c-a)
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Answer:
a^3 + b^3 + c^3 - 3abc = 0
when a+b+c = 0
by putting the value
a^3+ b^3+ c^3 = 3abc ......
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