Question

Prove that (A+B)’ . (A’+B) = A’.B’ algebraically?​

Answer 1

Explanation:

First taking NOT on both sides and then apply De-Morgan's Law on both sides:

L.H.S= (A+A'B)' =(A'.(A'B)') =(A'.(A+B')) //again applied de-morgan's law in previous step =(A'.A + A'B') =A'B' also apply De-morgans on RHS (A+B)' =A'B'

Thus LHS = RHS