prove that A×B=B ×A Which implies that A= B
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If A−B=B−A
A−B=B−A then for any x∈A−B=B−Ax∈A−B=B−A we x∈A;x∈B;x∉A;x∉Bx∈A;x∈B;x∉A;x∉B.
That's a contradiction so A−B=B−AA−B=B−A is empty.
Thus there are no elements in AA that are not in BB.
In other words AA is a subset of BB.
Likewise there are no elements of BBthat are in AA. So BB is a subset of AA.
So A=BA=B.
A−B=B−A then for any x∈A−B=B−Ax∈A−B=B−A we x∈A;x∈B;x∉A;x∉Bx∈A;x∈B;x∉A;x∉B.
That's a contradiction so A−B=B−AA−B=B−A is empty.
Thus there are no elements in AA that are not in BB.
In other words AA is a subset of BB.
Likewise there are no elements of BBthat are in AA. So BB is a subset of AA.
So A=BA=B.
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