Math, asked by ak7111168, 1 year ago

Prove that [a+b, b+c,c+a] =2[a b c].

Answers

Answered by mustafa3952
0

Answer:

[a+b,b+c,c+a]=[a+b×b+c×c+a]=[2a+2b+2c]=2[a+b+c](hence proved)

Answered by satyammtiwarii
1

Answer:

please see the image attached

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