Question

prove that [a+b,b+c,c+a] =2[abc]​

Answer 1

Answer:

it is equal, lets take a = 1, b = 2, c = 3.

Step-by-step explanation:

(a+b, b+c, a+c) = 2(abc)

[(1+2) + (2+3), (1+3)] = 2(1 x 2 x 3)

(3 + 5 + 4) = 2(6)

12 = 12

L.H.S = R.H.S