Question

prove that: (a+b+c)^3-a^3-b^3-c^3 = 3(a+b) (b+c) (c+a)​

Answer 1

Answer:

Please find below the solution for it:

Consider:

(a+b+c)^3 - a^3-b^3-c^3 = [(a+b)+c]3 – a3-b3-c3

(a+b)3+c3+3c(a+b)(a+b+c)-a3-b3-c3

a3+b3+3ab(a+b)+c3+3c(a+b)(a+b+c)-a3-b3-c3

a3+b3+c3+3ab(a+b)+3c(a+b)(a+b+c)-a3-b3-c3

3ab(a+b)+3c(a+b)(a+b+c) 3(a+b)[ab+c(a+b+c)]

3(a+b)[ab+ac+bc+c2] 3(a+b)[a(b+c)+c(b+c)]

3(a+b)(b+c)(c+a)

Hence Proved.

✨Hope it will help you.✨