Question

prove that (a+b+c)^3-a^3-b^3-c^3=3(a+b)(b+c)(c+a).

plz and this. URGENT!!!!!
plz HELP Brainly guys

Answer 1

LHS= (a+b+c+)³-a³-b³-c³
        = a³+b³+c³+3(a+b)(b+c)(c+a)-a³-b³-c³
        = 3(a+b)(b+c)(c+a)

RHS= 3(a+b)(b+c)(c+a)

∴ LHS=RHS

Answer 2

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