Math, asked by sarbjitkour50922, 9 months ago

prove that (a+b+c)³-(a³+b³+c³)=3(a+b)(b+c)(c+a)

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Answered by amru12

Answer:

The first approach would be to open and multiply ((a+b)+c)^3, which would be of form (a+b)^3 . Then take 3(a+b) common. You will after simplifying get RHS.

Answered by ashwinirkoogu

Answer:

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prove that (a+b+c)³-(a³+b³+c³)=3(a+b)(b+c)(c+a)​

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prove that (a+b+c)³-(a³+b³+c³)=3(a+b)(b+c)(c+a)