Question

prove that (a+b+c) ³-a³-b³-c³=3(a+b) (b+c) (c+a) ​

Answer 1

Step-by-step explanation:

we know that,(a+b+c)^3 = a^3+b^3+c^3+ 3(a+b)(b+c)(c+a)

subtract both sides by a^3+b^3+c^3 ,we get

(a+b+c)^3 -a^3-b^3-c^3 = 3(a+b)(b+c)(c+)

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