Math, asked by wwwbhavyjain, 15 days ago

Prove that (a + b + c)3-a3-b3-c3 = 3(a + b)
(b + c) (c + a).

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Answered by padmavathitamalampud

0

(a + b + c)3-a3-b3-c3 = 3(a + b)

(b + c) (c + a)

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