prove that
a+b+c
a-1 b-1+b-1 c-1 +c-1 a-1=abc
Answers
Answered by
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Step-by-step explanation:
Consider,
a
−1
b
−1
+b
−1
c
−1
+c
−1
a
−1
a+b+c
=
ab
1
+
bc
1
+
ca
1
a+b+c
-----since x
−1
=
x
1
=
abc
c
+
abc
a
+
cab
b
a+b+c
-----Multiply and divide each terms in the denominator by the missing terms. i.e., c,a,b respectively
=
abc
c+a+b
a+b+c
=
abc
1
1
=abc
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