prove that A+(B. C) =(A+B).(A+C)
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Answer:
(A + B) * (A’ + C)
→ AA’ + AC + A’B + BC
→ 0 + AC + A’B + BC
→ AC + CB + A’B
By the consensus theorem:
xy + yz + x’z = xy + x’z
Let A = x, B = z, C = y
→ AC + CB + A’B = xy + yz + x’z
→ AC + A’B = xy + x’z
Therefore, (A + B) * (A’ + C) = AC + A’B
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