Question

prove that (a+b+c)whole square​

Answer 1

Answer:

= (a+b+c) (a+b+c)

= a(a+b+c) b(a+b+c) c(a+b+c)

= a square+ ab+ac+ab+b square+bc+ac+bc+c square

= a square +b square +c square +ab+ab+bc+bc+ac+ac

= a square +b square +c square +2ab+2bc+2ac