prove that a b parallel to CD
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Step-by-step explanation:
1) Extend DC and join to BE at X.
2) Now angle CEB = 54°
3) AB || EF (ABE = FEB)
4) In Triangle CEX,
CEX + EXC = PCE
24° + EXC = 150°
EXC = 126°
5) EXC + BXC = 180° ( Linear Pair)
BXC + 126° = 180°
BXC = 54°
6) let BX be Transversal
BEX = BXC = 54°
AB || DX
So, DC is also parallel to AB
H.P
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