prove that (a+b)whole cube + (b+c) whole cube +(c+a) whole cube -3(a+b)(b+c)(c+a)=2(a cube + b cube + c cube -3abc)
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hey ,the solution is here
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hukam0685:
i multiplied those terms
how??
first multiply (a+b)(b+c), putting -3 outside of the brackets
on multiplying these u get. -3(ab+ac+b^2+bc)
sorry, I didn't understand
now again there are two brackets to multiply
it's okay thanks
bye
good night
i think you should practice to multiply these terms,first term of first bracket multipy to both terms one by one with another bracket,then second term of first bracket multiply with both terms one by one with second bracket,thus you find total for terms.hope you understand
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