prove that A-(BUC)=(A-B)N (A-C)
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Prove that A-(BUC) = (A-B) ∩ (A-C) Solution)
L.H.S = A - (B U C) A ∩ (B U C) c A ... x \in A-(B \cup C) \leftrightarrow x \in A \ wedge x \notin B \cup C ... Subtr'n}\end{array}.
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