Question

prove that A×(BUC)=(AUB)×(AUC)​

Answer 1

Step-by-step explanation:

let (x,y)∈A×(BUC)

now,(x,y)∈A×(BUC) =x∈A,y∈(BUC)

=x∈A,(y∈B or y∈C)

=(x∈A,y∈B)or(xA,y∈C)

=(x,y)∈A×Bor(x,y)∈A×C

=(x,y)∈(A×B)U(A×C)