Question

prove that A+C=A+A'C+BC

Answer 1

A+C = A+A'C+BC
=A+C+BC. ( third distributive law)
=A+C (1+B)
=A+C (1)
=A+C
HENCE PROVED.

Answer 2

A+C = A+A'C+BC=A+C+BC =A+C+BC. (THIRD DISTRIBUTION LAW) =A+C(1)=A+C HENCE PROVED