prove that a cos theta =b cos (c + theta) + c cos ( b + theta )
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helo guys its your answer
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In a triangle ABC, prove that for any angle θ, b cos(A−θ)+acos(B+θ)=ccosθ. · Answer · bcos( A−θ)+acos(B+θ) =b(cosA. cosθ+sinA. sinθ)+a (2)
In a triangle abc prove that for any angle theta b cos(A-theta) + a cos(B - theta) = c costheta
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