Math, asked by Anonymous, 1 year ago

prove that a cyclic parallelogram is a rectangle​

Answers

Answered by divyajain12
1

Step-by-step explanation:

Let quadrilateral PQRS be a cyclic parallelogram.

Therefore by THEOREM ON CYCLIC QUADRILATERAL ,

Angle P + angle R = 180 degree.......1 .

By the definition of a parallelogram ,

PQ || RS ...and ..QR || PS....................2 .

AND

QR = PS .....................................3.

THEREFORE From 1. 2. and 3.

QUADRILATERAL PQRS IS A RECTANGLE.....(BY DEFINITION OF A RECTANGLE)

Answered by itzOPgamer
0

Answer:

Step-by-step explanation:

Given,

ABCD is a cyclic parallelogram.

To prove,

ABCD is a rectangle.

Proof:

∠1+∠2=180°      ...Opposite angles of a cyclic parallelogram

Also, Opposite angles of a cyclic parallelogram are equal.

Thus,

∠1=∠2

⇒∠1+∠1=180°

⇒∠1=90°

hence proved

hope it helps u

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