Question

prove that a cyclic Parallelogram is a rectangle​

Answer 1

GIVEN:

AB=DC

AD=BC

TO PROVE:

ABCD IS A RECTANGLE

PROOF:

ANGLE D=ANGLE B. (OPPOSITE ANGLES OF PARALLELOGRAM ARE EQUAL)

ANGLE D+ ANGLE B=180 DEGREES. (OPPOSITE ANGLES OF PARALLELOGRAM ARE SUPPLEMENTARY)

ANGLE D + ANGLE D =180. (AXIOM 1: THINGS WHICH ARE EQUAL TO SAME THINGS ARE EQUAL TO ONE ANOTHER)

2(ANGLE D)=180

ANGLE D=90 DEGREES

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Answer 2

Answer:

Step-by-step explanation:

Given,

ABCD is a cyclic parallelogram.

To prove,

ABCD is a rectangle.

Proof:

∠1+∠2=180°      ...Opposite angles of a cyclic parallelogram

Also, Opposite angles of a cyclic parallelogram are equal.

Thus,

∠1=∠2

⇒∠1+∠1=180°

⇒∠1=90°