prove that a cyclic Parallelogram is a rectangle
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Answered by
3
Step-by-step explanation:
Given,
ABCD is a cyclic parallelogram.
To prove,
ABCD is a rectangle.
Proof:
∠1+∠2=180° ...Opposite angles of a cyclic parallelogram
Also, Opposite angles of a cyclic parallelogram are equal.
Thus,
∠1=∠2
⇒∠1+∠1=180°
⇒∠1=90°
One of the interior angle of the parallelogram is right angled. Thus,
ABCD is a rectangle.
Answered by
1
Answer:
Given,
ABCD is a cyclic parallelogram.
To prove,
ABCD is a rectangle.
Proof:
∠1+∠2=180° ...Opposite angles of a cyclic parallelogram
Also, Opposite angles of a cyclic parallelogram are equal.
Thus,
∠1=∠2
⇒∠1+∠1=180°
⇒∠1=90°
One of the interior angle of the parallelogram is right angled. Thus,
ABCD is a rectangle.
Step-by-step explanation:
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