prove that a cyclic parallelogram is always a rectangle
Answers
Answered by
100
AnswEr :-
Let ABCD is a cyclic quadrilateral such that it's diagonals AC & BD are the diameters of the circle.
Through the vertices A ,B ,C & D
as AC is diameter & angle in a semi circle is a right angle.
=> Angle ADC = 90 & Angle ABC = 90
Same as
BD is a diameter
=> Angle BCD = 90 & Angle BAD = 90
Thus , ABCD is a rectangle
Hence Proved
Similar questions