Question

prove that a cyclic Parallelogram is always a rectangle

Answer 1

Let ABCD be a cyclic parallelogram, Angle A+Angle C=180° (opposite angles of cyclic quadrilateral), equa.1.,. W.KT. opposite angles of a angles are equal. Angle A=C and AngleB=D. Then, from equ1. angle A=C=180° , A=A=180°, 2A=180°, {2/180}=90°, A=90°. Therefore, Parallelogram ABCD has one of its interior angle as 90°. So. it is a rectangle.

Answer 2

Answer:

Plz refer the given pic ...next step is as follows-                          

Step-by-step explanation:

So, abcd is a parallelogram with one angle as 90degrees .

Hence abcd is a rectangle ..