Prove that a cyclic parallelogram is always a triangle
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Please note your question has an error, it is to prove the quadrilateral is a rectangle not a triangle because proving a quadrilateral is a triangle is just impossible (and an offence to math)
Given: ABCD is a cyclic parallelogram
To prove: ABCD is a rectangle
Proof:
Since ABCD is a parallelogram
⇒∠A=∠C------eq.1(opp. ∠s of a parallelogram are equal)
Also, ABCD is cyclic
⇒∠A+∠C=180(opp.∠s of a cyclic quad. are supplementary)
∴∠A+∠A=180(from eq.1)
2∠A=180
∠A=90
∵ABCD is a parallelogram with one angle = 90
∴ABCD is a rectangle
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