Question

prove that a cyclic rhombus is a square​

Answer 1

Step-by-step explanation:

In Figure ABCD is Rhombus in circles

Isliya angle A+ angle C and Angle B+ Angle D. ( opposite angle of Rhombus Is Equal )

Angle A+ Angle C =180° ( opposite angle of cyclic Rhombus)

isliya Angle A+ Angle A = 180°

Angle A = 90°

And angle B + angle D = 180°. ( Opposite angle Of Cyclic Rhombus)

isliya Angle B+ Angle B = 180°

Angle B = 90°

isliya Angle A = Angle B = Angle C = Angle D = 90°

All angle of Rhombus is right angles then this is a square

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Answer 2

Answer:

Check picture

Step-by-step explanation:

Check picture